Is this the correct calculation?

[reptilelover0456]

[spooky13]

It looks like it

[lumpy]

Yes it is correct!

[erie-herps]

I don’t think so. If the banner’s correct (that’s what I’m going off of), I’m inferring that ultra and amel are allelic. In that case an animal can’t have a combined 3 or more copies of it. Which means amel het ultra is not possible. It’s right except amel het ultras would really be amel OR het amel het ultra. The link below might help if you’re confused how allelic morphs interact and inherit.

Cryptically confusing the science behind allelic genes

So, It’s common knowledge now that Cryptic is allelic with Clown, and also that Het Cryptic + Het Clown = Crypton. However, it seems there is still a fair bit of confusion floating around as we often get ads flagged over on MorphMarket where either the seller or flagger has a misunderstanding of how the genetics work. Especially when it comes to Crypton X Crypton pairings. It would be extremely helpful to have a comprehensive thread dedicated to this issue… @t_h_wyman @chesterhf .

Edit: I checked the marketplace and het amel het ultra combine to form ultramel. There aren’t very many ads that have amel het ultra, ultra het amel, or ultra amel which makes me think those few were mislabeled.

[lumpy]

Here it explains that for the morphs we are talking about. And yes, they are allelic so it is wrong.

Corn snake genetics Question

In order for a recessive mutation to be visually apparent, the snake will need two copies of the recessive genes. They get one copy from each parent. Ultra is a hybrid gene. Most corn snake genes are recessive, so in order to get a visually amel snake, there would be two copies of the amel gene sitting at the amel locus. It just so happens that the rat snake gene for ultra also sits at the same place as the amel gene. So if the parent is visually ultramel, it means that there is one gene for ult…

[solarserpents]

I usually use the calculator on iansvivarium.com for calculating ultramel combos, but your calculation does look correct. And yes, it’s impossible to have an amel het ultra, or vice versa, but the screenshot doesn’t show any combos like that. If you see snakes listed with those genes, they’ve been mislabeled. Here’s the iansvivarium.com calculation, which shows the same 8 possibilities.

[lumpy]

I honestly should have looked back at the screenshot to check if those were actual results on it. Lol so the calculation is correct, the results that @erie-herps listed cannot happen.

[lumpy]

Do you want to explain it in detail? I love when something is allelic, .

[solarserpents]

Which part?

[lumpy]

How it is correct? Specifically why you can’t have Amel het ultra. To help bring a full circle understanding about allelic genes.

[solarserpents]

Well, in order for a recessive gene to be visible, it needs to have two copies of the gene. Each gene has a different place on the chromosome that it sits. So for an amelanistic snake, it would have two copies of amel sitting at the amel location of the gene. Ultra is a gene from another species, so it just so happens that the place where ultra sits on the chromosome is the same place where amel sits. The spot only has room for two copies of a gene - so either two copies of amel, two copies of ultra, or one copy of each, which makes an ultramel. So an ultramel is technically het ultra and het amel. If you have an amel corn snake, the spot for amelanism on the chromosome is completely filled up with two copies of the amel gene, so it has no room for the ultra gene (so amel het ultra is not possible). If you have a visually ultra corn snake, it has two copies of ultra, so it can’t fit an amel gene there too (so ultra het amel is not possible). I hope that makes sense!

[lumpy]

It has no available slots, the only two are filled

Yes it makes sense! Thank you so much @solarserpents!

[reptilelover0456]

This makes a lot of sense, thank you!